mysql - creating class active dynamically in php -


i creating menu dynamically based on categories registered on database, need is: when click in link, option should have css class 'active', showing in page user , pages created dynamically. have no idea how because php student , couldn't find information in google "dynamically menus" thank much.

<nav class="menu">    <ul class="list">       <li class="line"><a id="item" href="index.php">home</a></li>         <?php        $categories = $db->select("select * tbl_category");        if($categories){           while ($result = $categories->fetch_assoc()){              echo <<<html              <li id="line" ><a class="item" href="categories.php?category=$result[id]">$result[name]</a></li> html;           }        }        ?>    </ul> <nav> 

first of all, you're looping through while loop , adding id of "line" each , every <li> element. suggest create unique id's each list item. don't necessary advocate using code way have it, example, here's code edited that:

if($categories){       $i = 1;       while ($result = $categories->fetch_assoc()){          $i++;          echo <<<html          <li id="line$i" ><a class="item" href="categories.php?category=$result[id]">$result[name]</a></li>          html;       } } 

then when clicks on link, use jquery this:

$(".item").click(function() {     $(this).parent('li').addclass('active'); }); 

Comments

Popular posts from this blog

sequelize.js - Sequelize group by with association includes id -

android - Robolectric "INTERNET permission is required" -

java - Android raising EPERM (Operation not permitted) when attempting to send UDP packet after network connection -