python - How to get the indices list of all NaN value in numpy array? -

say have numpy array defined as,

[[1,2,3,4], [2,3,nan,5], [nan,5,2,3]]

now want have list contains indices of missing values, [(1,2),(2,0)] @ case.

is there way can that?

x = np.array([[1,2,3,4],               [2,3,np.nan,5],               [np.nan,5,2,3]]) np.argwhere(np.isnan(x))

output:

array([[1, 2],        [2, 0]])

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