python - Unpacking list of lists generated by a zip into one list -

i again manipulating dataframes. here concatenate multiple dataframe using row common reference. want reorder columns "pairing" first 1 columns of each df together, , on. sake of data readability

here code:

df_list=[df_1,df_2,df_3]    return_df=pd.concat(df_list,axis=1, join='outer') dfcolumns_list=[df_1.columns,df_2.columns,df_3.columns] print (return_df.columns) print(dfcolumns_list) list_columns=np.array(list(zip(*dfcolumns_list))).reshape(1,-1)[0] print (list_columns) list_columns=np.array([x x in zip(*dfcolumns_list)]).reshape(1,-1)[0] print (list_columns) return_df=return_df[list_columns] 

my question related to:

list_columns=np.array(list(zip(*dfcolumns_list))).reshape(1,-1)[0] 

or alternatively

list_columns=np.array([x x in zip(*dfcolumns_list)]).reshape(1,-1)[0] 

it takes list of indexes, unpacks in zip, takes first element of each column index, outputs tuple/sublist contained in list, transforms array ,then reshapes rid of sublists cause

 return_df=return_df[list_columns] 

to break. @ last, call index 0 [0] allows retrieve final list np.array (which need reshape).

my question is: there nothing less ugly that? zip , similar functions, hate have no simple mean/trick unpack generated tuples/sublist reordering purposes.

(it came mind while redacting maybe df differently, give points that, main question still how doing more elegantly/with more pythonic syntax. [0] in end dirtiest of all...

you may zip column lists , flatten list of lists

list_columns = [ col cols in zip( *dfcolumns_list ) col in cols ]